用递归算法求1~n个连续自然数的乘积的代码如下,请选择合适的代码补全程序？（ ）def Chengji(n): if n <=1: return 1 else: return _____?______print(Chengji(3))
n*Chengji(n)
n*Chengji(n-1)
n*Chengji(n+1)
n×Chengji(n-1)
